Question

$\sqrt2x^{2} +7x+5\sqrt2=0\\factorise$

Answer 1

Answer:

$x = -\sqrt{2} , -\frac{5}{\sqrt{2} }$

Step-by-step explanation:

$\sqrt{2}x^{2} + 7x + 5\sqrt{2} = 0 \\\sqrt{2}x^{2} + 2x + 5x + 5\sqrt{2} = 0\\\sqrt{2}x(x+\sqrt{2}) + 5(x+\sqrt{2}) = 0\\(\sqrt{2}x+ 5)(x+\sqrt{2}) = 0$

$x = -\sqrt{2} , -\frac{5}{\sqrt{2} }$