Question

$\sqrt2x^{2} +7x + 5 \sqrt2 = 0$
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Answer 1

$\sqrt{2} {x}^{2} + 7x + 5 \sqrt{2} = 0 \\ \\ {x}^{2} + x = 0 \\ \\ \\ x = 0$

Answer 2

√(2)x2 + 7x + 5√2 = 0

= √(2)x2 + 5x + 2x + 5√2

= x(√2 x + 5) + √2(√2x + 5)

= (√2x + 5)(x + √2)

Roots of this equation are the values for which = (√2x + 5)(x + √2) = 0


hope it helps !!
Therefore, (√2x + 5)= 0 or (x + √2)=0

i.e., x = -5/√2 or x = -√2