![\sqrt2x + 2 = \sqrt[3]{2?} + 6 \sqrt2x + 2 = \sqrt[3]{2?} + 6](https://tex.z-dn.net/?f=+%5Csqrt2x+%2B+2+%3D++%5Csqrt%5B3%5D%7B2%3F%7D++%2B+6)
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⬆️⬆️⬆️⬆️⬆️ there is your answer.
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