![t {}^{2} + 4t = 21 t {}^{2} + 4t = 21](https://tex.z-dn.net/?f=t+%7B%7D%5E%7B2%7D++%2B+4t+%3D+21)
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Answer:
t²+4t = 21
t²+4t-21 = 0
t²+7t-3t-21 = 0
t(t+7)-3(t+7) = 0
(t+7)(t-3) = 0
Either t+7 = 0 or t-3 = 0
t+7 = 0 t-3 = 0
t = -7 t = 3
t = -7,3
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