Question

$t { }^{2} - 4t - 5 = 0$
How do we get the below solution of the above equation?
Plz explain by breaking it into steps
$(t + 1)(t - 5) = 0$
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Answer 1

Answer:

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Explanation:

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Answer 2

Answer:

By middle term splitting,

t^2 - 4t-5=0

t^2 + 1t - 5t -5=0

t(t+1) -5(t+1) = 0

(t+1)(t-5) =0

Therefore , answer = (t+1) (t-5)

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