Math, asked by lilyherna0419pefpoi, 1 year ago

 t^{2}  +8rt+ r^{2}
t=11 r=3

Answers

Answered by Moo1
1
t²+8rt + r²
=( t+r)² + 6rt
= 14² + 6*11*3
= 394 ans
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Answered by Anonymous
11
հҽվ!

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Given \: t = 11 , r = 3 \\ \\ {t}^{2} + 8rt + {r}^{2} \\ \\ {11}^{2} + 8(3)(11) + {3}^{2} \\ \\ 121 + 9 + (24 × 11) \\ \\ 121 + 9 + 264 \\ \\ 394

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