Math, asked by BrainlyWarrior, 1 year ago

tan^{-1} \dfrac{1}{\sqrt{x^{2} - 1}}

Write this in Simplest Form.

Answers

Answered by siddhartharao77
12

Answer:

(π/2) - sec⁻¹x

Step-by-step explanation:

Given:tan^{-1}(\frac{1}{\sqrt{x^2-1}})

Put x = secθ ⇒ θ = sec⁻¹x.

Now,

= tan⁻¹(1/√sec²θ - 1)

∴ We know that sec²θ = 1 + tan²θ

= tan⁻¹(1/√tan²θ)

= tan⁻¹(1/tan θ)

= tan⁻¹(cotθ)

= tan⁻¹(tan(90 - θ))

∴ We know that tan⁻¹(tanθ) = θ

= 90 - θ

= (π/2) - sec⁻¹x


Hope it helps!


BrainlyWarrior: Thank you sir:)
siddhartharao77: Welcome!
Answered by Anonymous
0

∴ We know that tan⁻¹(tanθ) = θ

= 90 - θ

= (π/2) - sec⁻¹x

Hope it helps!

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