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Answered by
12
Answer:
(π/2) - sec⁻¹x
Step-by-step explanation:
Put x = secθ ⇒ θ = sec⁻¹x.
Now,
= tan⁻¹(1/√sec²θ - 1)
∴ We know that sec²θ = 1 + tan²θ
= tan⁻¹(1/√tan²θ)
= tan⁻¹(1/tan θ)
= tan⁻¹(cotθ)
= tan⁻¹(tan(90 - θ))
∴ We know that tan⁻¹(tanθ) = θ
= 90 - θ
= (π/2) - sec⁻¹x
Hope it helps!
BrainlyWarrior:
Thank you sir:)
Answered by
0
∴ We know that tan⁻¹(tanθ) = θ
= 90 - θ
= (π/2) - sec⁻¹x
Hope it helps!
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