Question

${tan}^{ - 1} \frac{1}{x + y} + {tan}^{ - 1} \frac{y}{ {x }^{2} + xy + 1 } = {cot}^{ - 1} x$
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Answer 1

Answer:

Step-by-step explanation:

1/tan * 1/x+y + 1/tan * y/x²+xy+1.

1/tan x + tan y + y/tan x² + tan xy + tan.

Answer 2

Answer:

The answer is something and it is a number