Question

$tan( {cos}^{ - 1} ( \frac{1}{x} )) = sin( {cot}^{ - 1} ( \frac{1}{2} )) \: and \: x not \: equals \: to \: 0$
solve the following equation ​

Answer 1

Answer:

the answer for above question is x=30

Answer 2

Step-by-step explanation:

tan(cos^-1 1/x)=sin(cot^-1 1/2)

cos =adjacent / hypotenuse

1/x, hyp2=adj2+opp2

opp2= x2-1

opp=√x2-1

tan(tan-1 √x2-1/1) = √x^2-1------eq 1

sin(cot^-1 1/2)

cot = adj /opp = 1/2

hyp2= (1)^2+2^2

hyp= √5

sin (sin ^-1 2/√5)

2/√5------- eq 2

both shld be equal (eq 1= eq 2)

√x^2-1=2/√5

squaring on bith sides

x^2-1=4/5

x^2= 9/5

x=3/√5 is the ans

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