Question

$tell \: value \: of \: x$
$tell \: its \: urgent \: today \: only$
​

Answer 1

using Pythagoras theorem

(LM)² + (MN)² = (LN)²

$\\ {7}^{2} + {24}^{2} = {x}^{2} \\ \\ 49 + 576 = {x}^{2} \\ \\ {x}^{2} = 625 \\ \\ x = \sqrt{625 } \\ \\ x = 25 \: cm$

Hope this helps you

Answer 2

Answer:

$\huge\mathcal{\green{Hola!}}$

$\huge\mathfrak{\red{Answer}}$

$\rightarrow\small\bf x = 25units$

Step-by-step explanation:

$\huge\underline{\overline{\mid{\bold{\blue{\mathcal{ Question:- }}\mid}}}}$

From the given figure, find the value of x.

$\huge\underline{\overline{\mid{\bold{\blue{\mathcal{ Hint:- }}\mid}}}}$

From the figure we can observe that;

• the given triangle is a right angled triangle as / M = 90°
• Therefore, we will use the Pythagoras theorem.

$\huge\underline{\overline{\mid{\bold{\blue{\mathcal{ Pythagoras \ theorem:- }}\mid}}}}$

• ➝ In a right triangle, the square of the length of the hypotenuse is equal to the sum of the squares of the lengths of the other two sides.

$\huge\underline{\overline{\mid{\bold{\blue{\mathcal{ Required \ Solution:- }}\mid}}}}$

$\mathcal{\green{Here,}}$

Hypotenuse = x units

Base = 24 units

Perpendicular = 7 units

$\fbox{\purple{From \ Pythagoras \ theorem:}}$

${H}^{2} = {B}^{2} + {P}^{2}$

(LN)^2 = (MN)^2 + (LM)^2

$= > {x}^{2} = {24}^{2} + {7}^{2}$

${(x)}^{2} = 576 + 49$

${(x)}^{2} = 625$

$= > (x) = \sqrt{625}$

$x = 25 \: units$

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