Question

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Answer 1

Let's Start:- a) $(0.9p + 0.5q)^{2}$

                   ⇒ $(0.9p)^{2} + 2 * 0.9p * 0.5q + (0.5q)^{2}$            [ $(a + b)^{2} = a^{2} + 2ab + b^{2}$ ]

                   ⇒ 0.81p² + 0.9pq + 0.25q²

b) $(2x + 3) (2x - 3)$

⇒ $(2x)^{2} - (3)^{2}$                   [ $(a + b) (a - b) = a^{2} - b^{2}$ ]

⇒ $4x^{2} - 9$

Answer 2

Answer:

b answer

(2X + 3) (2X-3) formula (a+b) (a-b) = a^-b^

2X(2X-3) - 3(2X-3)

4X-5X - 5X-9

1X-5X-9

4X^-9

a answer

(0.9p-0.5q)^ formula (a-b) ^ =a^+b^-2ab

0.9p^ + 0.5q^ -2×0.9p^×0.5q^

0.81p^ + 0.25q^ -0.4pq