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Answer:
Given: AB∥CD
Construction: Draw a perpendicular on CD from B, meting CD at E
Thus, BE = AD
Now, In △ABD,
BD2=AD2+AB2
252=AD2+72
AD=24 cm
thus, BE=AD=24 cm
and CE=CD−AB=17−7=10 cm
Now, In △BCE
BC2=BE2+CE2
BC2=242+102
BC2=676
BC=26 cm
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