. A ball is thrown vertically upwards. It goes to a height 20 m and then returns to the
ground. Taking acceleration due to gravity g to be 10 ms , find :
(a) the initial velocity of the ball
(b) the final velocity of the ball on reaching the ground and
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Answer:
Given:
s (distance) = 20m
a (acceleration) = 10m/s²
v (initial) = 0
u (final) =?
a) initial velocity of the ball :
v²-u²= 2as ( using 3rd equation of motion)
0²-u² = 2×10×20
=> u = √20×20
=> u = 20
Thus, initial v. of the ball = 20m/s
b) final velocity of the ball after reaching the ground :
v²-u² = 2as (using 3rd equation of motion.)
v²-0² = 2×10×20
=> v = -√2×10×20
=> v = -√20×20
=> v = -20.
Thus,final v. of the ball = 20m/s ( in negetive direction)
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