Question

$\:$
Answer this question ⤴️
$\: \:$
​

Answer 1

Number of charges = 3

So,

Net electric potential at the centre of tye equilateral triangle is

= 3 × V

where,

V = kq

r

Here, k = (1/4πε₀)

q = q is given

r = (√3)d/4

Hence. Vₙₑₜ = 3 × (1/4πε₀)(q)/(√3d/4)

= (1/4πε₀)(√3q/d)

Hope u liked my answer

Pls mark me as brainliest

Thanks.

Answer 2

Answer:

exam undi reading

tinna✌☺