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Answered by Ganesh094
6

❍ Option ⓒ μA

\sf\alpha  = 180° - 90° - A = 90 - A

\sf r =90 -  \alpha  = A

• From snell's law

\sfμ _{1}sini = \sfμ _{1}sinr

\sf1sini = μ sinA

• For small angle

 \sf  i = μA

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