IN FIGURE (iv) WHICH PAIRS OF TRIANGLES ARE CONGRUENT BY "SAS"
{ SIDE- ANGLE- SIDE } CONGRUENCE CONDITION ? IF CONGRUENT,WRITE THE CONGRUENCE OF THE TWO TRIANGLES IN SYMBOLIC FORM...
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Base² + Perpendicular²
So, QS² = PQ² + PS²
Also, QS² = RS² + QR²
On comparing both,
PQ² + PS² = RS² + QR²
PQ² + 4² = RS² + 4²
PQ² = RS²
so, PQ = RS
Now in ΔQPS and ΔSRQ,
PQ = RS ( Proved above)
angle QPS = angle QRS ( Both 90 )
QR = SP (Both 4cm)
Hence by SAS criterion,
ΔQPS ≅ ΔSRQ.
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hey mate!!
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