Question

.Question 6. 'Stability of a crystal is reflected in the magnitude of its melting points'. Comment.
Collect melting points of solid water, ethyl alcohol, diethyl ether and methane from a data book. What can you say about the intermolecular forces between these molecules?

Answer 1

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$\huge{ \boxed { \boxed { \underline{ \bf \purple {\mathbb {ANSWER}}}}}}]$

${ \underline{ \bf \green{Melting\:points \:of\: substances}}}$

• Water = 273K.

• Ethyl alcohol = 155•7K.

• Diethyl ether = 156•8K.

• Methane = 90•5K.

The stability of crystals depends up on the packing of the atoms.

$\huge{ \boxed { \boxed { \underline{ \bf \orange {\mathbb {EXPLAINATION }}}}}}]$

If there are strong force of attraction between the constituent particles then greater the stability.

${ \underline{ \bf \green{Water}}}$

strong intermolecular hydrogen bonding.

${ \underline{ \bf \blue{Ethyl\:alcohol}}}$

strong intermolecular hydrogen bonding.

${ \underline{ \bf \red{Diethyl\:ether}}}$

it is a polar molecule so there is dipole –dipole attraction.

${ \underline{ \bf \pink{Methane}}}$

It is a non–polar molecule so that there is weak van der Waal's forces (London dispersion forces).

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${ \underline{ \bf \green{FOLLOW\:ME}}}$

${ \underline{ \bf \blue{VISHU\:PANDAT}}}]$

Answer 2

${ \underline{ \bf \green{Melting\:points \:of\: substances}}}$

• Water = 273K.

• Ethyl alcohol = 155•7K.

• Diethyl ether = 156•8K.

• Methane = 90•5K.

The stability of crystals depends up on the packing of the atoms.