Question

$\boxed {\begin {array}{c}\\ \sf Prove\: that \\ \sf {a^2+b^2= (a+b)^2-2ab} \\ \end {array}}$​

Answer 1

Answer:

(a+b)2=(a+b)(a+b)

               =(a+b)(a)+(a+b)(b)

               =a2+ab+ab+b2

               =a2+2ab+b2

Answer 2

☆Answer

$\red{a^2+b^2= (a+b)^2-2ab} \\ \color{orange} \leadsto \: (a + b) {}^{2} - 2ab \\ \color{gold} \leadsto \: {a}^{2} + 2ab + {b}^{2} - 2ab \\ \color{plum}\leadsto \: {a}^{2} + 2ab - 2ab + {b}^{2} \\ \color{pink} \leadsto \: {a}^{2} + 0 + {b}^{2} \\ \color{cyan} \leadsto \: {a}^{2} + {b}^{2} \\ \sf \: \color{green}Hence ,\: Proved.$