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Given :-
Equation is x/3 + y/4 = 1
To find :-
Area of the triangle formed with coordinate axis of the given line.
Solution :-
We are given,
⇒ x/3 + y/4 = 1
Multiply this equation with 12
⇒ 4x + 3y = 12
Now, if we substitute x = 0, we get :
⇒ 4(0) + 3y = 12
⇒ 3y = 12
⇒ y = 12/3
⇒ y = 4
If we substitute y = 0 , we get :
⇒ 4x + 3(0) = 12
⇒ 4x = 12
⇒ x = 12/4
⇒ x = 3
Now we get two coordinates on the given line which are enough to plot the graph.
- ( 3, 0)
- ( 0, 4)
[See the graph in attachment.]
The vertices of the triangle formed are (3,0) , (0,4) and (0,0)
Assume the coordinates as :-
- (3,0) = (x1 , y1)
- (0,4) = (x2, y2)
- (0,0) = (x3, y3)
Area of the triangle is given by,
⇒ Ar. ∆ = 1/2 | x1(y2-y3)+ x2(y3-y1) +x3(y1-y3) |
⇒ Ar. ∆ = 1/2 | 3(4-0) + 0(0-0) + 0(0-0) |
⇒ Ar. ∆ = 1/2 | 12 |
⇒Ar. ∆ = 1/2 × 12
⇒ Ar. ∆ = 6
Hence the area of the given triangle is 6 unit square.
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