Question

$\textbf{Find the zeroes of a quadratic polynomial 6x2 — 7x — 3}$

Answer 1

Answer:

let p(x)=6x²-7x-3

=6x²-9x+2x-3

=3x(2x-3)+1(2x-3)

=(3x+1)(2x-3)

to find zeroes put p(x)=0

3x+1=0

x=-1/3

2x-3=0

x=3/2

zeroes of quadratic polynomial are 3/2 and -1/3

Answer 2

Answer:

3/2 and -1/3

Step-by-step explanation:

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