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Answered by
17
Hey user, here is your answer...
____________________________________
Prove that
How is this possible?
Let's see...
Proof:-
= ( 100 - 100 ) / ( 100 - 100 )
= 10^2 - 10^2 / 10 ( 10 - 10 )
= ( 10 + 10 ) ( 10 - 10 ) / 10 ( 10 - 10 )
( using a^2 - b^2 identity )
= 10 + 10 / 10
= 20 / 10
= 2
Hence, it is proved that,
= 2
____________________________________
Hope it helps.
Thanks for the question.
____________________________________
Prove that
How is this possible?
Let's see...
Proof:-
= ( 100 - 100 ) / ( 100 - 100 )
= 10^2 - 10^2 / 10 ( 10 - 10 )
= ( 10 + 10 ) ( 10 - 10 ) / 10 ( 10 - 10 )
( using a^2 - b^2 identity )
= 10 + 10 / 10
= 20 / 10
= 2
Hence, it is proved that,
= 2
____________________________________
Hope it helps.
Thanks for the question.
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Answered by
4
☢☢☢ HEY THERE ☢☢☢
Answer:
This may not be mathematically correct but I can hit a try!
Step-by-step explanation:
0/0=a²-a²/a²-a²
0/0=(a+a)(a-a)/a(a-a)
Now cancelling a-a-
0/0=2a/a=2
Drawbacks:
a-a/a-a=0/0 which cannot be cancelled since 0/0≠1.
So it is mathematically impossible to prove 0/0=2.
☢☢☢ HOPE IT HELPS ☢☢☢
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