Question

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Answer 1

Answer:

Question 1:

• Probability of getting ace of black = 1/26
• Probability of getting a red face card = 3/26

Question 2:

• Probability of getting green marble = 0
• Probability of getting yellow marble = 6/17

Solution:

Question 1:

From a well shuffled 52 playing cards, a card is drawn randomly then find the probability of

(1) getting an ace of black.

(2) getting a red face card.

Solution:

Ace cards are the cards that are marked with A. There are 4 ace cards (2 black and 2 red) in total.

So, Probability of getting ace of black = 2 ÷ 52

$\implies \boxed{\bf{Probability \: of \: getting \: an \: ace \: of \: black = \dfrac{1}{26}}}$

Red face card:

There are 6 red face cards

So probability of getting a red face card = 6 ÷ 52.

On simplifying,

$\therefore\: \boxed{\bf{Probability \: of \: getting \: red\:face\:card=\dfrac{3}{26}}}$

Question 2:

Total number of marbles = 3 + 8 + 6 = 17

$\sf{Probabilty=\dfrac{Number \: of \: favourable \: outcomes}{Total \: number \: of \: outcomes}}$

$\implies \sf{Probability_{(green \: marble)} = \dfrac{0}{17}}$

$\implies \boxed{\bf{Probability_{(green \: marble)} = 0}}$

Similarly,

$\dashrightarrow \: \: \: \sf{Probability_{(yellow \: marble)}=\dfrac{6}{17}}$

$\therefore \: \boxed{\bf{Probability \: of \: getting \: yellow \: marble=\dfrac{6}{17}}}$

Answer 2

⚝ Question given :

• From a well shuffled 52 playing cards, a card is drawn randomly then find the probability of – 1) getting an ace of black 2) getting a red face card

⚝ Given that :

• From a well shuffled 52 playing cards, a card is drawn randomly.

⚝ Need to find :

• we have to calculate and find out the the probability of – 1) getting an ace of black 2) getting a red face card.

⚝ Formula used :

★ P (E) = Number of favourable outcomes / Total Number of outcomes. ★

Here,

• P is the probability
• E is the event

⚝ Performing Calculation :

1. Getting an ace of black

• Total number of cards = 52

• In cards, there are 2 ace cards.

substituting the values in the formula : we get,

↬ Probability = 2 / 52

↬ Probability = 1/26

◆ Hence, the probability of getting an ace card is 1/26.

2) Getting a red face card.

• Total number of cards = 52

• In cards, there are 6 red-faced cards.

substituting the values in the formula : we get,

↬ Probability = 6 / 52

↬ Probability = 3/26

◆ Hence, the probability of getting a red face card is 3/26.

⚝ Question Given :

• A bad contains 3 red marbles 8 black marbles and 6 yellow marbles, A marble is choosen randomly then find the probability of – getting a green marbles 2. getting a yellow marbles.

⚝ Given that :

• A bad contains 3 red marbles 8 black marbles and 6 yellow marble.

⚝ Need to find :

• we have to calculate and find out the the probability of – 1. getting a green marbles 2. getting a yellow marbles.

⚝ Formula used :

★ P (E) = Number of favourable outcomes / Total Number of outcomes. ★

Here,

• P is the probability
• E is the event

⚝ Performing Calculation :

1. Getting a green marbles

• Total Number of marbles = 3 + 8 + 6 = 17 marbles

• In bag, there a 0 green marbles.

substituting the values in the formula : we get,

↬ Probability = 0 / 17

↬ Probability = 0 [ impossible event ]

◆ Hence, the probability of getting a green marbles 0.

2. Getting a yellow marbles

• Total Number of marbles = 17

• In bag, there a 6 yellow marbles.

substituting the values in the formula : we get,

↬ Probability = 6 / 17

◆ Hence, the probability of getting a yellow marbles is 6/17.

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