Question

$\ \textless \ br /\ \textgreater \ \ \textless \ br /\ \textgreater \ {\displaystyle {\int \cfrac{\sec^2x}{\cosec^2x}dx}}∫\ \textless \ br /\ \textgreater$


Integrate this​

Answer 1

${\displaystyle{\int \dfrac{\sec^2x}{\cosec^2x}dx}}$

${\displaystyle{\int \dfrac{\sin^2x}{\cos^2x}dx}}$

${\displaystyle{\int {\tan^2x•dx}}}$

${\displaystyle{\boxed{\left(1+\tan^2x=\sec^2x\right)}}}$

${\displaystyle{\int (\sec^2x-1)dx}}$

${\displaystyle{\int \sec^2x \int 1•dx}}$

${\displaystyle{\tan x-x+c}}$

Answer 2

The Eraser Tool has three options: the Erase Mode, Eraser Shape, and the Faucet. The Eraser Shape option defines both the size and shape of the eraser

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