Math, asked by tagorbisen, 1 day ago


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if a man Travels at a speed of 30 km per hour he reaches his destination 10 minutes late and if he travels at a speed of 40 km per hour in this destination 10 minutes early the distance travel eat ​

Answers

Answered by siddiquafirdous2013
1

Let the distance be x km.

Then, correct time at a speed of

30 km / h = x30 - 1060

Correct time at a speed of 42 km /h

= x42 + 1060

=> x30 - 1060 = x42 + 1060

=> x30 - x42 = 26

=> x(12)1260 = 26

=> 72 x = 1260 × 2

=> x = 1260×272 => x = 35 km

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Answered by venom0136
1

Let T is the actual time taken to reach the destination by man.

case 1 : if the speed of man , u = 30 km/h , he reaches his destination 10 min late .

e.g., distance between man and destination point , S = speed of man × time taken

= 30 × (T + 1/6) km [ as you know, 10min = 10/60 hour = 1/6 hour ]

so, S = 30(T + 1/6) - (1)

case 2 : if the speed of man, v = 42 km/h , he reaches his destination 10 minutes early.

e.g.,. distance between man and destination point , S = speed of man × Time taken

= 42 × (T - 1/6) km

so, S = 42(T - 1/6) -(2)

from equations (1) and (2),

30(T + 1/6) = 42(T - 1/6)

or, 10T + 10/6 = 14T - 14/6

or, 10/6 + 14/6 = 14T - 10T

or, 24/6 = 4T

or, T = 1 hour

putting T = 1 in equation (1),

S = 30(1 + 1/6) = 30 × 7/6 = 35 km

hence, The distance travelled is 35 km

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