Question

$the \: length \: and \: breadth \: of \: a \: rectangle \: are \: 60cm \: and \: 30cm \: repectively.find \: the \: ratio \: of \: its \\ \\ \\ \\ a.length \: to \: breadth \\ \\ length \: to \: perimeter \: \\ \\ c.area \: to \: perimeter$
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Answer 1

Step-by-step explanation:

Given that,

Number of turns N=60

Length l=20cm

Width b=10cm

Magnetic field B=0.5T

Rotation per min f=1800

We know that,

ϕ=(ABcosθ)N

ϕ=NABcosωt

dt

−dϕ

=ε

ε=−

dt

d(NABcosωt)

ε=−ABω(−sinωt)N

ε=NABωsinωt

ω=2πf

ε=2πfNABsinωt

ε

max

=2πfNAB

ε

max

=2×3.14×60×(20×10×10

−4

)×0.5×30

ε

max

=113.04volt

Hence, the maximum induced emf is 113.04volt

Answer 2

Answer:

number to bhej bhen ya formula mang rahi hai