Question

$the \: recpewcal \: of \: \frac{1}{6} where \: b \: \: 0 \: \: is$
Fill in the blanks
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Answer 1

Answer:

GivenA(−1,−1)=(x

1

,y

1

),

B(6,1)=(x

2

,y

2

),C(8,8)=(x

3

,y

3

)

andD(x,y)areverticesofaRhombus.

\begin{gathered} x = x_{1} + x_{3} - x_{2} \\= -1 + 8 - 6 \\= -7 + 8 \\= 1 \end{gathered}

x=x

1

+x

3

−x

2

=−1+8−6

=−7+8

=1

\begin{gathered} y = y_{1} + y_{3} - y_{2} \\= -1 + 8 - 1 \\= -2 + 8 \\= 6 \end{gathered}

y=y

1

+y

3

−y

2

=−1+8−1

=−2+8

=6

Therefore.,

\begin{gathered} \red{ Co-ordinates \:of \:point \:D(x,y) }\\\green {= (1,6) }\end{gathered}

Co−ordinatesofpointD(x,y)

=(1,6)

Answer 2

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