Question

$the \: sum \: of \: ages \: of \: two \\ friends \: is \: 20years \: four \\ years \: ago \: the \: product \: of \\ their \: ages \: in \: years \: was \\ 48 \: is \: the \: above \: situation \\ is \: possible \: if \: so \: determine \\ their \: present \: ages$
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Answer 1

Let x and y be the ages of both friends respectively

Ages of them four years ago =x-4 and y-4 resp.

Product of their ages 4 yrs ago=

(x-4)(y-4)=xy-4x-4y+16

But product=48

xy-4x-4y+16=48

xy-4(x-y)=32------1

Sum of present ages=x+y=20

x=20-y---------2

Substitution of 1 in 2,

(20-y)(y)-4(20-y-y)=32

20y-y^2-80-8y=32

12y-y^2-48=0

y^2-12y+48=0---(multiplying by-1)

Answer 2

Step-by-step explanation:

Solution is given in above pic

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