Three consecutive multiple of 7 are x,x+7,x+14
According to the problem
x+x+7+x+14=777
3x+21=777
3x=7777-21
3x=756
(1st multiple)=x=756/3=252 therefore x=252
(2ndmultiple)=x+7
=252+7
=257
(3rd multiple)=x+14
=252+14
=266
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