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Zero of ( x - 1 ) = 1.
P( x ) = 4 x ^ 3 + 3 x ^ 2 - 4 x + k
P ( 1 ) = 4 * 1 ^ 3 + 3 * 1 ^ 2 - 4 * 1 + k = 0
4 * 1 + 3 * 1 - 4 + k = 0
4 + 3 - 4 + k = 0
3 + k = 0
k = - 3
P( x ) = 4 x ^ 3 + 3 x ^ 2 - 4 x + k
P ( 1 ) = 4 * 1 ^ 3 + 3 * 1 ^ 2 - 4 * 1 + k = 0
4 * 1 + 3 * 1 - 4 + k = 0
4 + 3 - 4 + k = 0
3 + k = 0
k = - 3
Anonymous:
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Answered by
1
If x-1 is a factor of
4x³+3x²-4x+k=0
4x³+3x²-4x=-k
x-1=0
x=1,
Putting 1 in the equation we get,
4*1³+3*1²-4*1+k=0
4+3-4+k=0
7-4+k=0
3+k=0
k=-3.
Hope it helps.
Please mark my answer as brainliest if it's correct.
Thanks!
4x³+3x²-4x+k=0
4x³+3x²-4x=-k
x-1=0
x=1,
Putting 1 in the equation we get,
4*1³+3*1²-4*1+k=0
4+3-4+k=0
7-4+k=0
3+k=0
k=-3.
Hope it helps.
Please mark my answer as brainliest if it's correct.
Thanks!
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