Physics, asked by Anonymous, 1 year ago

The \: velocity - time \: relation \: \\ of \: a \: body \: starting \: from \: rest \\ is \: given \: by \: v = {k}^{2} {t}^{ \frac{3}{2} } , \: \\ where \: k = \sqrt{2} \frac{ {m}^{ \frac{1}{2} } }{ {s}^{ \frac{5}{4} } } .The \: \\ distance \: traversed \: in \: 4 \: \\ seconds \: is \\ (1) \: 2.00 \: m \\ (2)2.56 \: m \\ (3)25.6 \: m \\ (4)256 \: m

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Answered by MrJ109
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