Question

${\tt\blue{probability}}$

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if three dice are thrown, the probability that they show the numbers in A.P​

Answer 1

Answer:

1/18

Step-by-step explanation:

A.P. with common diff one are =4=(123)(234)(345)(456)

A.P. with common diff 2 are =2=(135)(246)

A.P. with common diff 0 are =6

⇒P=2+4+6/216=1/18

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