Question

$\tt\huge\rightleftharpoons \: \red{Question} \:$
The sum of integers from 1 to 300 which is divisible by 2 or 5​..
​

Answer 1

Hi there!

Your Answer :-

The Numbers Are :-

(2,4,5,6,8,10,..................300)

$\sf\red{Divisiblity \: \: by \: \: 2 \to }$

• 2,4,6,8.................300
• 2(1,2,3...................150)
• 22650

$\sf\red{Divisiblity \: \: by \: \: 5 \to }$

• 5,10,15,20.............300
• 5(1,2,3,4................150)
• 9150

As The Numbers Which Are Divisible By 2 and 5, They Must be Divisible By 10.

$\sf\red{Divisiblity \: \: by \: \: </strong><strong>1</strong><strong>0</strong><strong> \to }$

• 10,20,30...........300
• 10(1,2,3,4............30)
• 4650

So, The Numbers Which Are Divisible By 2 and 5 are :-

$\sf\green{22650 + 9150 - 4650}$

$\sf\blue{27150}$

Answer 2

$\tt\huge\rightleftharpoons \: \blue{Question} \:$

The sum of integers from 1 to 300 which is divisible by 2 or 5..

$\tt\huge\rightleftharpoons \: \blue{Answer} \:$

Given : integers from 1 to 300 which are divisible by 2 or 5

To find : Sum of integers

Solution :

integers from 1 to 300

Divisible by 2  

2 , 4  , 6  , .........................................., 300

Sum

= 2+ 4  + 6  + .........................................+300

= 2(1 + 2 + 3 +.............................+ 150)

= 2 ( 150)(151)/2

= 22650

Divisible by 5

5 , 10  , 15  , .........................................., 300

Sum

= 5+ 10 + 15  + .........................................+300

= 5(1 + 2 + 3 +.............................+ 60)

= 5 (60)(61)/2

= 9150

Both contains number divisible by 10

Divisible by 10

 10  , 20  , .........................................., 300

Sum

=   10 +20  + .........................................+300

= 10(1 + 2 + 3 +.............................+ 30)

= 10 (30)(31)/2

= 4650

sum of integers from 1 to 300 which are divisible by 2 or 5

= 22650 + 9150 - 4650

=27150

27150  is   sum of integers from 1 to 300 which are divisible by 2 or 5

HOPE SO IT IS HELPFUL..✌️❣️..