Q.No.2: Find the radius of the circle in which a central angle of 60° intercepts an arc of length 37.4 cm (use π = 22/7).
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➪ Given
➪Length of the arc = l = 37.4 cm
➪Central angle = θ = 60° = 60π/180 radian = π/3 radians
➪We know that,
➪r = l/θ
➪= (37.4 × 3)/π
➪= (37.4 × 3 × 7)/22
➪= 35.7cm
➪Hence, the radius of the circle is 35.7cm.
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solution
Here l = 37.4 cm, θ = 60° = π/3 rad But r = l/θ = (37.4 x 3)/π = (34.4 x 3 x 7)/22 = 35.7cm
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