Question

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The population of a small locality was 4000 in 1979 and 4500 in 1981, By what percent had the population increase?


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Answer 1

Question :-

The population of a small locality was 4000 in 1979 and 4500 in 1981, By what percent had the population increase?

To find :-

By what percent had the population increase

Given :-

• population of small locality in 1979 = 4000

• population of small locality in 1981 = 4500

solution :-

so increase in population = 4500 - 4000 = 500

thus percent increase in population

$\dashrightarrow\sf \: = \frac{500}{4000} \times 100 \\ \\ \\ \dashrightarrow\sf \: \cancel\dfrac { 50} { 4} = 12.5$

therefore the population of the locality increased by 12.5 In two years

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