Question

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Answer 1

Answer:

233.4mm,0.017

Explanation: HEY THERE< HOPE IT HELPS>

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Given:

p∘H2O=23.8mm,W2=50g,Mw2(urea)=60gmol−1

W1=850g,Mw2(H2O)=18gmol−1

Applying Raoult's law and using another relation :

p∘−psps=n2n1=W2/Mw2W1/Mw1=50/60850/18=0.17

Substituting the value of p∘=23.8mm

23.8−pSpS=0.017

or 23.8−pS=0.017pS⇒1.017pS=23.8

or pS=23.81.01723.4mm

Thus, the vapour pressure of water in the solution =23.4mm.

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Answer 2

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