Question

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Answer 1

Answer:

Correct Question:-

Haemoglobin contains 0.25% iron/weight the molecular mass of hemoglobin is 89600 calculate the no. of Iron (Fe) atoms present per molecule of hemoglobin??

Required Answer:-

Molecular mass of Haemoglobin = 89600

Percentage of Iron = 0.25% / weight. This means the total mass of Iron out of the total molecular mass of Haemoglobin is 0.25% of 89600.

GiveN mass of Iron:

= 0.25% × 89600

= 25/10000 × 89600

= 1/400 × 89600

= 224 gm of Iron.

Moles of Iron:

= Given Mass / Atomic mass

= 224 gm / 56 gm

= 4 moles.

Now here, 1 mole of Haemoglobin contains 4 moles of Iron (Fe). Then 1 molecule of Haemoglobin will have 4 atoms of Fe.

Hence:-

No. of Iron atoms present per molecule of hemoglobin = 4

Explanation:

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Answer 2

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