Math, asked by LovelysHeart, 1 month ago

{\tt { {\underline{\underline{\huge{ǫᴜEsTɪᴏɴ:}}}}}} \: \: \: \:
 \:  \:  \:  \:
From a team of 6 students, in how many ways can we choose a captain and vice-captain assuming one person can not hold more than one position?
 \:  \:  \:  \:
⚠️ Dᴏɴ'ᴛ Sᴘᴀᴍ ⚠️​

Answers

Answered by MysticalFuzZie
9

{\tt { {\underline{\underline{\huge{Answer:}}}}}} \: \: \: \:

 \: \: \: \:

From a team of 6 students, two students are to be chosen in such a way that one student will hold only one position.

Here, the no. of ways of choosing a captain and vice-captain is the permutation of 6 different things taken 2 at a time.

So,6P2= 6! / ( 6 -2 )! = 6! / 4! = 30

Thanks

Step-by-step explanation:

Mark as brainiest

\ Shanaya

Answered by BrainlyThunder
22

Team of students = 6

No of Students can hold more than one position = x

So,

To let us know the no. of position we must take 6 different things to take 2 at a time

So,

6P2= 6! / ( 6 -2 )! = 6! / 4! = 30

Similar questions