From a team of 6 students, in how many ways can we choose a captain and vice-captain assuming one person can not hold more than one position?
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From a team of 6 students, two students are to be chosen in such a way that one student will hold only one position.
Here, the no. of ways of choosing a captain and vice-captain is the permutation of 6 different things taken 2 at a time.
So,6P2= 6! / ( 6 -2 )! = 6! / 4! = 30
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Team of students = 6
No of Students can hold more than one position = x
So,
To let us know the no. of position we must take 6 different things to take 2 at a time
So,
6P2= 6! / ( 6 -2 )! = 6! / 4! = 30
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