Question

$\tt \: Urgently,,,,,, Please \: help \: me!!!!$
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Answer 1

Given :

• Present age of Ashok is equal to the square of his son age.
• One year ago , Ashok was eight times as old as his son.

What To Find :

• Present ages of Ashok and his son

Solution :

Let assume the present age of Ashok be x

Let assume the present age of his son be y

✯ According to the question

$\boxed{\sf \large\bf\red{ x \: \: = \: {y}^{2} } \rm \:} \: \rm \: equation \: \: 1$

One year ago Mr. Ashok was eight times as old as his son.

☯ So ,

• Age of Ashok = (x - 1)
• Age of his son = 8 (y - 1)

☯ Therefore :

x - 1 = 8(y - 1)

x - 1 = 8y - 8

8 - 1 = 8y - x

7 = 8y - x

✯ Now , Re - arrange in descending order

• 8y - x = 7

$\boxed{\sf \large\bf\red{ 8y - x = 7 } \rm \:} \: \rm \:-- \: equation \: \: 2$

✯ Solving equation 1 and equation 2

8y - y² = 7

☯ Again , Re - arrange in descending order

y² - 8y = 7

Solving this quadratic equation by Splitting the middle term method.

⇛y² - 8y + 7 = 0

⇛y² - 7y - y + 7 = 0

⇛y(y - 7) - 1(y - 7) = 0

⇛(y - 1) (y - 7) = 0

⇛y = 1 or 7

⬤ Consider age of son is 7 years

✯ Putting the values of y in equation 1

⇝x = y²

⇝x = 7²

⇝x = 49

⬤ Hence , the age of Ashok is 49 years

Final Answer :

• Age of Ashok is 49 years
• Age of his son is 7 years

Answer 2

Answer:

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