Question

$\tt \:  y \: = \: sinx \: + \: 1$

↪️Find Range ​

Answer 1

To find :-

• Range of " y "

⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀

Solution :-

❍We are given that,

• $\sf \:  y \: = \: sinx \: + \: 1$

❍We know,

$:\implies \sf\: - 1 \leqslant sinx \leqslant 1$

[ Adding 1 ]

$:\implies \sf \: 1 - 1 \leqslant sinx + 1 \leqslant 1 + 1$

$:\implies \sf\: 0 \leqslant sinx + 1 \leqslant 2$

$:\implies \sf \: 0 \leqslant y \leqslant 2$

$:\implies \boxed{ \purple{\sf \: Range \: of \: y \: \in \: [0, \: 2]}}$

⠀⠀⠀⠀⠀⠀━━━━━━━━━━━━━━━━━━━⠀⠀⠀⠀⠀⠀⠀⠀

Answer 2

Explanation:

➵cot (15° - A) + tan(15° + A) =

The SHM force relation “F = -kx” is a generic form of equation for linear SHM – not specific to block-spring system. In the case of block-spring system, “k” is the spring constant. This point is clarified to emphasize that relations that we shall be developing in this module applies to all linear SHM and not to a specific case.