Question

$two \: objects \: of \: masses \: 100g \: and \: 200g \: are \: moving \: along \: the \: same \: line \: and \: direction \: with \: velocities \: of \: {2ms}^{ - 1 } \: and \: {1ms}^{ - 1} \: respectively .they \: collide \: and \: after \: the \: collision \: the \: first \: object \: moves \: at \: the \: velocity \: of \: {1.67ms}^{ - 1}. \: determine \: the \: velocity \: of \: the \: second \: object.$help me with this question
​

Answer 1

Explanation:

write full answer

mark me brainliest

Answer 2

Answer:

Given

Mass of one of the objects (m1) = 100 g = 0.1 kg

Mass of the other object (m2) = 200 g = 0.2 kg

Velocity of m1 before collision (v1) = 2 m/s

Velocity of m2 before collision (v2) = 1 m/s

Velocity of m1 after collision (v3) = 1.67 m/s

Find out

Velocity of m2 after collision= v4

Solution

According to the law of conservation of momentum:

Total momentum before collision = Total momentum after collision

Therefore, m1v1 + m2v2 = m1v3 + m2v4

On sustitututing the known and given values we get

2(0.1) + 1(0.2) = 1.67(0.1) + v4 × (0.2)

0.4 = 0.167 + 0.2 × v4

v4= 1.165 m/s

Answer

Hence, the velocity of the second object becomes 1.165 m/s after the collision.

Explanation:

Mark me as brainliest.