Question

$\underline{\Huge{\purple{\sf Question:-}}}$

Three sides of a triangle measure 8 m ,15 m,17 m.

Find the area and Perimeter of the triangle .

Note:-

Answer must be in 60+words and explained.

Spammed answers will be deleted.​

Answer 1

Answer:

$\sf \: Given \begin {cases} \sf sides \: of \triangle \: = 8 \: m \: \: \: 15 \: m \: and \: 17 \: m \end{cases}$

_______________________

As we know that

$\tiny \sf \:Perimeter \: of \triangle \: = a \: + b \: + c$

$\sf \: Perimeter = 8 + 15 + 17$

$\sf \pink \star{Perimeter = 40 \: m}$

Now

Finding Area

$\sf \: Semiperimeter = \dfrac{p}{2}$

$\sf \: Semiperimeter \: = \dfrac{40}{2}$

$\sf \: Semiperimeter \: = 20 \: m$

Now,

$\sf \: Area = \sqrt{s(s - a)(s - b)(s - c)}$

$\sf \: Area = \sqrt{20(20 - 8)(20 - 15)(20 - 17)}$

$\sf \: Area = \sqrt{20 \times 12 \times 5 \times 3}$

$\sf \: Area = \sqrt{3,600}$

$\sf \: area \: = 60 \: {m}^{2}$

Answer 2

$\huge\red{\mid{\underline{\overline{\texttt{Question}}}\mid}}$

❥A triangular field has sides measure 8m ,15m and 17m.Find the perimeter and area of the field.

$\huge\pink{\mid{\fbox{\tt{Answer↴}}\mid}}$

⇒PERIMETER = 40m

⇒AREA =

$\huge\mathtt{\fcolorbox{pink}{cyan}{\purple{Solution ࿐}}}$

GIVEN -

→TRIANGLE OF SIDES = 8m, 15m and 17m

TO FIND -

❥PERIMETER OF TRIANGLE = ?

❥AREA OF TRIANGLE = ?

FORMULA USED -

➔AREA OF TRIANGLE =

$\tt \implies\sqrt{s(s - a)(s - b)(s - c)}$

where,

s = semiperimeter

a , b and c = sides

➔SEMI PERIMETER = PERIMETER/2

➔PERIMETER = a + b + c (assuming the sides as a,b and c)

SOLUTION -

➙PERIMETER OF TRIANGLE = a + b + c (sum of all sides)

➙PERIMETER OF TRIANGLE = (8 + 15 + 17)m

➣PERIMETER OF TRIANGLE = 40m

➣SEMI PERIMETER = 40/2 = 20m

AREA OF TRIANGLE =

$\tt\implies\sqrt{s(s - a)(s - b)(s - c)}$

$\tt\implies \sqrt{20(20 - 8)(20 - 15)(20 - 17}$

$\tt\implies \sqrt{20(12)(5)(3)}$

$\tt\implies\sqrt{3600}$

$\tt\implies 60{m}^{2}$

HENCE ,

$\tt➣AREA \: OF \: TRIANGLE \: = \: 60m²$

$\tt➣PERIMETER \: OF \: TRIANGLE \: = \: 40m$