Question

${\underline{\huge\rm\pink{Question :}}}$

In the adjoining figure, ABCD is a parallelogram in which
$\sf \angle CAD = 40°$
$\sf \angle BAC = 35°$
$\sf \angle COD = 65°$

Then calculate the following :

$\sf (i)\angle ABD = 40°$
$\sf(ii)\angle BDC = 40°$
$\sf (iii)\angle ACB = 40°$
$\sf \angle CBD = 40°$

NOTE :

◉ Honesty is best policy(don't spam/uncopied)

◉ Well Explanation.


​

Answer 1

Step-by-step explanation:

1) it is by alternate interior angle

Answer 2

Answer:

it by alternate interior angle.

Step-by-step explanation:

hope you got it.

please follow meee and follow back.