Question

${\underline{\huge\rm\pink{Question :}}}$

In the adjoining figure, ABCD is a parallelogram in which
$\sf \angle CAD = 40°$
$\sf \angle BAC = 35°$
$\sf \angle COD = 65°$

Then calculate the following :

$\sf (i)\angle ABD = 40°$
$\sf(ii)\angle BDC = 40°$
$\sf (iii)\angle ACB = 40°$
$\sf (iv)\angle CBD = 40°$

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◉ Well Explanation.

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Answer 1

115°+40°+CBO=180°

155°+CBD=180°

CBD=25°

HOPE IT HELP YOU

Answer 2

Step-by-step explanation:

an angle is of 180°

so that all the angle when we sum all of this then we got the 180° angle that why total sum of parallelogram is 180°