Question

$\underline{\Huge{\sf Question:-}}$

The difference between circumstances of two circles is 44 meters. The sum of their radius is 77 meters.

Find their circumstances :)

Note:-

Spammed answers will be deleted ​

Answer 1

Required Answer:-

Correct Question:

• The difference between circumference of two circles is 44m. The sum of their radius is 77m. Find their circumference.

Solution:

Let the radii of two circles measures x and y cm where x is the radius of the larger circle.

Perimeter of a circle = 2πr where r is the radius.

Therefore,

➡ Difference between their circumference = 44m

➡ 2πx - 2πy = 44

➡ 2π(x - y) = 44

➡ 2 × 22/7 × (x - y) = 44

➡ x - y = 44 × 7/44

➡ x - y = 7 . . . .(i)

Also,

➡ Sum of their radius = 77cm

➡ x + y = 77 . . . .(ii)

Adding both equations (i) and (ii), we get,

➡ 2x = 84

➡ x = 84/2

➡ x = 42 cm.

Substituting the value of x in (i), we get,

➡ 42 - y = 7

➡ y = 35 cm.

Hence, the radii of two circles measures 42 cm and 35 cm.

Perimeter of the first circle will be,

= 2π × 42 cm

= 2 × 22/7 × 42 cm

= 44 × 6 cm

= 264 cm.

Perimeter of the second circle will be,

= 2π × 35 cm

= 44/7 × 35 cm

= 44 × 5 cm

= 220 cm

★ Hence, the perimeter of the circles will be 264 cm and 220 cm.

Answer:

• The perimeter of the circles will be 264 cm and 220 cm.

Answer 2

Appropriate Question:-

• The difference between circumference of two circles is 44 meters. The sum of their radius is 77 meters. Find their circumference

Supposition:-

• $\sf R_{1}$ = x
• $\sf R_{2}$ = y

According to the question:-

• $\sf R_{1}+R_{2} = 77$

$\longrightarrow$ $\underline{\boxed{\sf x+y = 77}}$ ... $\sf eq_{1}$

• $\sf 2πR_{1} - 2πR_{2} = 44$

$\longrightarrow$ $\sf 2πx-2πy = 44$

$\longrightarrow$ $\sf 2π(x-y) = 44$

$\longrightarrow$ $\sf 2×\dfrac{22}{7}(x-y)=44$

$\longrightarrow$ $\sf \dfrac{44}{7}(x-y) = 44$

$\longrightarrow$ $\sf x-y = \dfrac{44×7}{44}$

$\longrightarrow$ $\underline{\boxed{\sf x-7 = 7}}$ ... $\sf eq_{2}$

Solution:-

let's eliminate y from both the equations by using elimination Method

:$\implies$$\sf x+y = 77$

:$\implies$$\sf x-y = 7$

:$\implies$$\sf 2x = 84$

:$\implies$ $\sf x = 42$ = $\sf R_{1}$

now, putting the value of X in eq. 1 :-

:$\implies$$\sf x+y = 77$

:$\implies$$\sf 42+y=77$

:$\implies$$\sf y = 35$ = $\sf R_{2}$

hence, the radius of 1st circle = 42cm and the 2nd circle = 35cm

Now, let's find the areas of the respective circles

$\longrightarrow$ $\underline{\boxed{\sf area\:of\: circle = 2πr}}$

$\dashrightarrow$ $\sf area\:of\:circle_{1} = 2×\dfrac{22}{7}×42$

$\dashrightarrow$ $\sf area\:of\:circle_{1} = 264cm²$

$\dashrightarrow$ $\sf area\:of\:circle_{2} = 2×\dfrac{22}{7}×35$

$\dashrightarrow$ $\sf area\:of\:circle_{2} = 220cm²$