Question

$\underline\mathcal\colorbox{lime}{{\color{red}{★Question ★}}}$

A circular flower bed is surrounded by a path 4 m wide. The diameter of the flower bed is 66 m. What is the area of this path?
(π = 3.14)

Note:
➠ Kindly Don't Spam
➠ Need Quality Answer ​

Answer 1

________________________

We have given that, the diameter of the flower bed d = 66 meter= 2r

r = 33 meter

Find out, Area (A) of the path =?

$\huge \underline \mathfrak{answer}$

Width of the path which is surrounded by the circular flower bed = 4 m

Now the radius of total circular flower bed including the path R = (33+4)= 37 m

Now the required area A

$= π{R^2-r^2} \\ A = π {37^2–33^2}= π [(37+33)(37–33)] \\ A =\frac{22}{7} \times {70×4}= 880$square m.

$\fbox \pink {d}\fbox \green {a} \fbox \blue {r} \fbox \red {k} \fbox \purple {s} \fbox \orange {h} \fbox \pink {a} \fbox \green{d} \fbox \blue{o} \fbox \red{w} \fbox \purple{7083}$

Answer 2

Diameter of the circular flower bed=66m

∴ Radius of circular flower bed(r)= 2/66 =33m

∴ Radius of circular flower bed with 4 m

wide path (R)=33+4=37m

According to the question,

Area of path=Area of bigger circle−Area of smaller circle =πR 2 −πr 2 =π(R 2 −r 2 )

=π[(37) 2 −(33) 2 ]

=3.14[(37+33)(37−33)] [∵a 2−b 2 =(a+b)(a−b)]

=3.14×70×4

=879.20m 2.

Therefore, the area of the path is 879.20m²