Question

$\underline{\text{Question : }}$

A coil having area $A$ and resistance $R Ω$ is connected with a galvanometer of resistance $4RQ$ in series. This combination is moved in time $t$ seconds from a magnetic flux $W_{1}$ weber to $W_{2}$ weber. The average induced current in the circuit is

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Answer 1

Answer:

$\huge \green{\frac{W_2 - W_1}{5Rt} }$

Explanation:

When magnetic flux through a coil Changes then

there is a induced Emf in coil , magnitude of emf is given by

$\epsilon = | \frac{d\overrightarrow{B}}{dt} | \\ and \\ \epsilon _{avg} = \frac{ \Delta \overrightarrow{B}}{ \Delta t} = \frac{W_2 - W_1}{t}$

Now net resistance of coil = R + 4R = 5R

We have induced emf , resistance and need induced current So use Ohm's Law

$I _{avg}= \frac{ \epsilon _{avg}}{R} \\ \\ = \frac{W_2 - W_1}{t(5R)} \\ \\ = \frac{W_2 - W_1}{5Rt}$

The direction of induced current is such that it opposes change in magnetic flux .

Answer 2

Explanation:

given :

• coil having area = A

• resistance = 4 RQ

to find :

• The average induced current in the circuit is

solution :

• E = dB/ dt

• e = ∆ B /∆t = w2 - w 1 /t

• resistance coil = R + 4R = 5R

• I = E/R

• w2- w1 / t( 5R)

• = w2- w1/ 5 rt