Question

$\underline{use \: the \: square \: root \: property \: to \: slove \: the \: equation}$
${t - 4)² = 12$

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Answer 1

Answer:

(t-4)²= 12

(t-4)= ±2√3

thus, when +ve,

t-4=2√3

t= 2√3+4

t= 2(2+√3)

thus,when -ve,

t-4=-2√3

t= 4-2√3

t=2(2-√3)

Answer 2

Answer:

(t-4)2= 12

(t-4)2= 12(t-4)= ±2v3

(t-4)2= 12(t-4)= ±2v3thus, when +ve,

(t-4)2= 12(t-4)= ±2v3thus, when +ve,t-4=23

(t-4)2= 12(t-4)= ±2v3thus, when +ve,t-4=23t=2+3+4

(t-4)2= 12(t-4)= ±2v3thus, when +ve,t-4=23t=2+3+4t=2(2+13)

(t-4)2= 12(t-4)= ±2v3thus, when +ve,t-4=23t=2+3+4t=2(2+13)thus,when -ve,

(t-4)2= 12(t-4)= ±2v3thus, when +ve,t-4=23t=2+3+4t=2(2+13)thus,when -ve,t-4=2v3

(t-4)2= 12(t-4)= ±2v3thus, when +ve,t-4=23t=2+3+4t=2(2+13)thus,when -ve,t-4=2v3t=4-2v3

(t-4)2= 12(t-4)= ±2v3thus, when +ve,t-4=23t=2+3+4t=2(2+13)thus,when -ve,t-4=2v3t=4-2v3t=2(2-13)