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Ryanwatson7:
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Answered by
23
((2)^3)^n -7n -1
= (8)^n -7n -1
= (1 +7)^n -7n -1
= nC0 + nC1(7) + nC2(7)^2...... + nCn(7)^n - 7n -1
= 1 + 7n + (7)^2 (nCo + nC1(7)..... nCn(7)^(n-2)) -7n - 1
= (7)^2 (nCo + nC1(7)..... nCn(7)^(n-2))
= 49 (nCo + nC1(7)..... nCn(7)^(n-2))
= 49m
So it is a multiple.
= (8)^n -7n -1
= (1 +7)^n -7n -1
= nC0 + nC1(7) + nC2(7)^2...... + nCn(7)^n - 7n -1
= 1 + 7n + (7)^2 (nCo + nC1(7)..... nCn(7)^(n-2)) -7n - 1
= (7)^2 (nCo + nC1(7)..... nCn(7)^(n-2))
= 49 (nCo + nC1(7)..... nCn(7)^(n-2))
= 49m
So it is a multiple.
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