Science, asked by IISLEEPINGBEAUTYII, 14 days ago


what \: i s \: the \: value \: of \: \\  the \: discriminat \: for \:  \\  \sqrt{2 {x}^{2} }  - 5x +  \sqrt{2}  = 0?


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Answers

Answered by shantakarpurkayastha
4

Answer:

D=b^-4ac

Explanation:

 - 4 { }^{2}  - 4 \times  \sqrt{ { \\ }^{2} }

Answered by Anonymous
34

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a=\sqrt{2} \\ b=-5\\ c=\sqrt{2}\\ D=b^{2}  - 4ac \\ D=(5)^{2} -4(\sqrt{2})(\sqrt{2} )\\ D= 25-8——————4 X \sqrt{2}X\sqrt{2}  =8

D=17

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