Math, asked by arshpreetsinghjaswal, 1 day ago


which \: is \: the \: following \: s \: an \: irrationall \: number  \\ 0.3796 \\ 7.988478  \\  \\ \sqrt{225 }  \\  \sqrt{23}
answer of question​

Answers

Answered by Anonymous
60

{\underline {\boxed {\bf {\pink {\bigstar~Answer}}}}}

We know that :-

  • The rational numbers are the numbers that can be represented or show as the quotient or fraction of form p/q of two integers such that q is not equal to zero ( q ≠ 0 ) and this rational numbers are either terminating or repeating decimals.

  • The irrational numbers are any real number that can not be represented or show as the quotient or fraction of form p/q of two integers such that q is not equal to zero ( q ≠ 0 ) and can be expressed as infinite decimal expansion with no repeating digit or group of digits.The decimal expansion of this numbers is non - terminating non - recurring .

 \\ {\underline{\rule{300pt}{9pt}}}

{\underline {\boxed {\bf {\red {\bigstar~Example \:  =  1}}}}}

{\underline {\boxed {\bf { {\bigstar~   \: 0.3796}}}}}

Explanation :-

  • The decimal expansion of this given number is terminating that is it is decimal number that contains a finite number of digits after the decimal point .

Therefore :-

{\underline {\boxed {\bf { {\bigstar~   \: 0.3796 \: is \: a \: rational \: number}}}}}

 \\ {\underline{\rule{300pt}{9pt}}}

{\underline {\boxed {\bf {\red {\bigstar~Example \:  =  3}}}}}

{\underline {\boxed {\bf { {\bigstar~   \:  \sqrt{225} }}}}}

Explanation :-

 \rm \implies \:  \sqrt{225}  = 15 =  \dfrac{15}{1}  =  \dfrac{p}{q}

  • The given number can be represented or show as the quotient or fraction of form p/q of two integers such that q is not equal to zero ( q ≠ 0 )

Therefore :-

{\underline {\boxed {\bf { {\bigstar~   \:  \sqrt{225}  \: is \: a \: rational \: number}}}}}

 \\ {\underline{\rule{300pt}{9pt}}}

{\underline {\boxed {\bf {\red {\bigstar~Example \:  =  4}}}}}

{\underline {\boxed {\bf { {\bigstar~   \:  \sqrt{23} }}}}}

Explanation :

 \rm \implies \sqrt{23}  = 4.79583152331..

  • The above number is also not perfect square number

  • The decimal expansion of this numbers is non - terminating non - recurring and it can not be represented or show as the quotient or fraction of form p/q of two integers such that q is not equal to zero ( q ≠ 0 ) and can be expressed as infinite decimal expansion with no repeating digit or group of digits

Therefore :-

{\underline {\boxed {\bf { {\bigstar~   \:  \sqrt{23} \: is \: a \: irrational \: number }}}}}

 \\ {\underline{\rule{300pt}{9pt}}}


Yuseong: Well done!
Answered by Anonymous
2

Step-by-step explanation:

which \: is \: the \: following \: s \: an \: irrationall \: number \\ 0.3796 \\ 7.988478 \\ \\ \sqrt{225 } \\ \sqrt{23}

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